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7x^2=364
We move all terms to the left:
7x^2-(364)=0
a = 7; b = 0; c = -364;
Δ = b2-4ac
Δ = 02-4·7·(-364)
Δ = 10192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10192}=\sqrt{784*13}=\sqrt{784}*\sqrt{13}=28\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{13}}{2*7}=\frac{0-28\sqrt{13}}{14} =-\frac{28\sqrt{13}}{14} =-2\sqrt{13} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{13}}{2*7}=\frac{0+28\sqrt{13}}{14} =\frac{28\sqrt{13}}{14} =2\sqrt{13} $
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